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Question

The enthalpy change for the reaction of 50 mL of ethylene with 50 mL of H2 at 1.5 atm pressure is 0.31 kJ. The value of U is:

A
302 J
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B
302 J
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C
302 kJ
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D
none of these
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Solution

The correct option is B 302 J
The reaction is given by,
C2H4+H2C2H6

Here the ratio of reactant is 1:1 and product is also forming in ratio of 1.
Therefore, 50 ml of ethylene on reaction with 50 ml of H2 will produce 50 ml. of ethane.

Change in volume is 50ml (ethane)-100ml (C2H4+H2) = 50ml= 0.05L

So,PΔV=1.5×0.05=0.075Latm7.5 Jolues

Now,

ΔU=ΔHPΔV=0.31kJ+7.5J=302J


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