The enthalpy change for two reactions are given by the equations- 2Crs- 3 2 O 2 g- Cr 2 O 3 s- H-1130kJ Cs- 1 2 O 2 g- COg- H-110kJWhat is the enthalpy change in kJ for the following reaction- 3Cs- Cr 2 O 3 s- 2Crs-3COg

The correct option is A +800kJ 3C(s)+ 3 2 O _ 2 (g)⟶ 3CO(g); Δ H= 330kJ Cr _ 2 O _ 3 (s)⟶ 2Cr(s)+ 3 2 O _ 2 (g); Δ H=+1130kJ On adding abov ...

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Hess' Law

The enthalpy ...

Question

The enthalpy change for two reactions are given by the equations:
$2 C r (s) + \frac{3}{2} O_{2} (g) ⟶ {C r}_{2} O_{3} (s); Δ H = - 1130 k J$
$C (s) + \frac{1}{2} O_{2} (g) ⟶ C O (g); Δ H = - 110 k J$
What is the enthalpy change in $k J$ for the following reaction?
$3 C (s) + {C r}_{2} O_{3} (s) ⟶ 2 C r (s) + 3 C O (g)$

- 1460 k J

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- 1800 k J

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+ 800 k J

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- 1020 k J

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+ 1460 k J

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Similar questions

{A l}_{2} O_{3} (s)

{C r}_{2} O_{3} (s)

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{m o l}^{- 1}

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{m o l}^{- 1}

{F e}_{2} O_{3} (s) + 3 H_{2} (g) ⟶ 3 H_{2} O (l) + 2 F e (s)

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C (g) + O_{2} (g) \to C O_{2} (g)

H_{2} O (g) + C (g) \to C O (g) + H_{2} (g)

Δ H = + 131 k J

C O (g) + \frac{1}{2} O_{2} (g) \to {C O}_{2} (g)

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H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (g)

Δ H = - 242 k J

Δ H_{c o m b} C

I

C (s) + O_{2} (g) ⟶ C O_{2} (g)

I I

C (s) + \frac{1}{2} O_{2} (g) ⟶ C O (g)

I I I

C O (g) + \frac{1}{2} O_{2} (g) ⟶ C O_{2} (g)

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