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Heat of Reaction

The enthalpy ...

Question

The enthalpy change of solution of $B a C l_{2} \cdot 2 H_{2} O$ and $B a C l_{2}$ are $8.8$ and $- 20.6$ kJ/mol respectively. Calculator enthalpy change of hydration of $B a C l_{2}$ into $B a C l_{2} \cdot 2 H_{2} O$ .

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Solution

1. $B a C l_{2} . H_{2} O (s) + a q$ $\to$ $B a C l_{2} (a q)$
$Δ S o l H_{1}^{0} = 8.8$ $K J m o l^{- 1}$
2. $B a C l_{2} (s) + a q$ $\to$ $B a C l_{2} (a q)$
$Δ S o l H_{2}^{0} = - 20.6$ $K J m o l^{- 1}$
according to question
$B a C l_{2} (s)$ $+ 2 H_{2} O \to$ $B a C l_{2} .2 H_{2} O (s)$
$Δ h y d H^{0} = ?$
according to hess law
$Δ h y d H^{0}$ $+ 8 .8 K J m o l^{-} 1 = - 20.6 K J m o l^{-} 1$

$Δ h y d H^{0}$ $= - 29.4 K J m o l^{-} 1$

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