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Byju's Answer
Standard XII
Chemistry
Heat of Reaction
The enthalpy ...
Question
The enthalpy change of solution of
B
a
C
l
2
⋅
2
H
2
O
and
B
a
C
l
2
are
8.8
and
−
20.6
kJ/mol respectively. Calculator enthalpy change of hydration of
B
a
C
l
2
into
B
a
C
l
2
⋅
2
H
2
O
.
Open in App
Solution
1.
B
a
C
l
2
.
H
2
O
(
s
)
+
a
q
→
B
a
C
l
2
(
a
q
)
Δ
S
o
l
H
0
1
=
8.8
K
J
m
o
l
−
1
2.
B
a
C
l
2
(
s
)
+
a
q
→
B
a
C
l
2
(
a
q
)
Δ
S
o
l
H
0
2
=
−
20.6
K
J
m
o
l
−
1
according to question
B
a
C
l
2
(
s
)
+
2
H
2
O
→
B
a
C
l
2
.2
H
2
O
(
s
)
Δ
h
y
d
H
0
=
?
according to hess law
Δ
h
y
d
H
0
+
8
.8
K
J
m
o
l
−
1
=
−
20.6
K
J
m
o
l
−
1
Δ
h
y
d
H
0
=
−
29.4
K
J
m
o
l
−
1
Suggest Corrections
1
Similar questions
Q.
The enthalpy of solution of
B
a
C
l
2
(
s
)
and
B
a
C
l
2
.2
H
2
O
(
s
)
are – 20.6 and 8.8 kJ
m
o
l
−
1
respectively, the enthalpy change for the hydration of
B
a
C
l
2
(
s
)
is:
Q.
The enthalpy of solution of
B
a
C
l
2
(
s
)
and
B
a
C
l
2
.2
H
2
O
(
s
)
are – 20.6 and 8.8 kJ
m
o
l
−
1
respectively, the enthalpy change for the hydration of
B
a
C
l
2
(
s
)
is:
Q.
The enthalpy of solution of
B
a
C
l
2
(
s
)
and
B
a
C
l
2
.2
H
2
O
(
s
)
are
−
20.6
and
8.8
k
J
m
o
l
−
1
respectively.
The enthalpy change for the rection
B
a
C
l
2
(
s
)
+
2
H
2
O
(
a
q
)
→
B
a
C
l
2
(
s
)
.2
H
2
O
(
s
)
will be:
Q.
The enthalpy of solution of
B
a
C
l
2
(
s
)
and
B
a
C
l
2
.2
H
2
O
(
s
)
are -20.6 and 8.8KJ/mol respectively. The enthalpy change for the reaction
B
a
C
l
2
(
s
)
+
2
H
2
O
⟶
B
a
C
l
2
.2
H
2
O
Q.
Enthalpies of solution of
B
a
C
l
2
.2
H
2
O
and
B
a
C
l
2
are
8.8
and
−
20.6
k
J
m
o
l
−
1
respectively. Calculate the heat of hydration of
B
a
C
l
2
to
B
a
C
l
2
.2
H
2
O
.
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