The enthalpy changes for two reactions are given by the equations- 2Crs-1 1 2 O 2 g- Cr 2 O 3 s- H-1130kJ Cs- 1 2 O 2 g- COg- H-110kJWhat is the enthalpy change- in kJ- for the reaction- 3Cs- Cr 2 O 3 s- 2Crs-3COg

The correct option is C +800kJ Cr _ 2 O _ 3 (s)⟶ 2Cr(s)+ 3 2 O _ 2 (g);Δ H=+1130kJ 3C(s)+ 3 2 O _ 2 (g)⟶ 3CO(g);Δ H= 330kJ Adding both equa ...

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Hess' Law

The enthalpy ...

Question

The enthalpy changes for two reactions are given by the equations:
$2 C r (s) + 1 \frac{1}{2} O_{2} (g) ⟶ {C r}_{2} O_{3} (s); Δ H = - 1130 k J$
$C (s) + \frac{1}{2} O_{2} (g) ⟶ C O (g); Δ H = - 110 k J$
What is the enthalpy change, in $k J$ , for the reaction?
$3 C (s) + {C r}_{2} O_{3} (s) ⟶ 2 C r (s) + 3 C O (g)$

- 1460 k J

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- 800 k J

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+ 800 k J

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+ 1020 k J

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+ 1460 k J

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