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Byju's Answer
Standard XII
Chemistry
Heat of Formation
The enthalpy ...
Question
The enthalpy formation of
H
2
O
(
l
)
is
−
285.7
kJ
m
o
l
−
1
and enthalpy of neutralization of strong acid and base is
−
57.6
kJ
m
o
l
−
1
. what is the enthalpy of formation of
O
H
−
1
ions
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Solution
H
2
(
g
)
+
1
2
O
2
(
g
)
⟶
H
2
O
(
l
)
;
Δ
H
=
−
285.7
k
J
/
m
o
l
.
.
.
.
.
(
1
)
Neutralisation of strong acid and base-
H
+
(
a
q
.
)
+
O
H
−
(
a
q
.
)
⟶
H
2
O
(
l
)
;
Δ
H
=
−
57.6
k
J
/
m
o
l
H
2
O
(
l
)
⟶
H
+
(
a
q
.
)
+
O
H
−
(
a
q
.
)
;
Δ
H
=
57.6
k
J
/
m
o
l
.
.
.
.
.
(
2
)
Adding
e
q
n
(
1
)
&
(
2
)
, we have
H
2
(
g
)
+
1
2
O
2
(
g
)
+
H
2
O
(
l
)
⟶
H
2
O
(
l
)
+
H
+
(
a
q
.
)
+
O
H
−
(
a
q
.
)
;
Δ
H
=
[
(
−
285.7
)
+
57.6
]
k
J
/
m
o
l
H
2
(
g
)
+
1
2
O
2
(
g
)
⟶
H
+
(
a
q
.
)
+
O
H
−
(
a
q
.
)
;
Δ
H
=
−
228.1
k
J
/
m
o
l
Hence the enthalpy of formation of
O
H
−
ion is
−
228.1
k
J
/
m
o
l
.
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0
Similar questions
Q.
The enthalpy of neutralization of a strong acid by a strong base is
−
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−
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. The enthalpy of formation of water and hydrogen ions are
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and
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Q.
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Q.
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and enthalpy of neutralization of the strong acid with a strong base is
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Q.
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Given : enthalpy of formation of
C
O
2
(
g
)
and
H
2
O
(
l
)
are
−
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k
J
/
m
o
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−
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J
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Q.
The enthalpies of formation of
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H
(
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(
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(
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o
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The value of bond enthalpy
O
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H
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