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Standard XII

Chemistry

State (Phase) of Alkanes

The enthalpy ...

Question

The enthalpy of formation of isoprene is
(Neglect resonance in isoprene)
Given : $C - H = 98.8$ k Cal ; $H - H = 104$ k Cal;
$C - C = 83$ k Cal; $C = C = 147$ k Cal &
$C (s) \to C (g) = 171$ k Cal.

+ 30.4

k Cal

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+ 25.3

k Cal

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+ 20.6

k Cal

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+ 50.3

k Cal

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Solution

The correct option is C $+ 20.6$ k Cal
As we know,
$5 C (s) + 4 H_{2} (g) \to C_{5} H_{8}$
so formation enthalpy is = $171 * 5 + 4 * 104 - (2 * 83 - 2 * 147 - 98.8 * 8) = 20.6 k C a l$

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The enthalpy of formation of isoprene is(Neglect resonance in isoprene)Given : C−H=98.8 k Cal ; H−H=104 k Cal;C−C=83 k Cal; C=C=147 k Cal &C(s)→C(g)=171 k Cal.

The correct option is C +20.6 k CalAs we know,5C(s)+4H2(g)→C5H8so formation enthalpy is = 171∗5+4∗104−(2∗83−2∗147−98.8∗8)=20.6kCal

The enthalpy of formation of isoprene is
(Neglect resonance in isoprene)
Given : $C - H = 98.8$ k Cal ; $H - H = 104$ k Cal;
$C - C = 83$ k Cal; $C = C = 147$ k Cal &
$C (s) \to C (g) = 171$ k Cal.

The correct option is C $+ 20.6$ k Cal
As we know,
$5 C (s) + 4 H_{2} (g) \to C_{5} H_{8}$
so formation enthalpy is = $171 * 5 + 4 * 104 - (2 * 83 - 2 * 147 - 98.8 * 8) = 20.6 k C a l$