You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Physics

Specific Heat Capacity

The enthalpy ...

Question

The enthalpy of fusion for ice is 334 J/g. How much is heat is absorbed if 10.0 grams of ice melts at $0^{\circ} C$ ?

3340 J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

334 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

33400 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 3340 J
3340J heat is absorbed if 10.0 grams of ice melts at 0 deg C.
The enthalpy of fusion is 334 J/g.
When 10.0 g of ice melts at 0 deg C, the heat absorbed is $10.0 \times 334 = 3340$ J

Suggest Corrections

Similar questions

Q. Latent heat of fusion of ice is 333 J/g at

0^{\circ}

C. Entropy change in entropy units when one mole of ice melts is nearly

Q. The amount of heat required to convert

1

g of ice at

- 10^{0} C

into steam at

100^{0} C

is (approximately): (specific heat of water

=

4.187

J/g

^{0}

C, latent heat of fusion

=

334

J/g , latent heat of vaporization

=

2260

J/g, specific heat of ice

=

2.03

J/g) :

10

g of ice at 0

^{o}

C absorbs

5460

J of heat energy to melt and change to water at

50

^{o}

C. Calculate the specific latent heat of fusion of ice. Specific heat capacity of water is

4200

J kg

^{- 1}

^{- 1}

Q. 10 g of ice at

0^{\circ} C

absorbed 5460 J of heat to melt and change into water at

50^{\circ} C

. Calculate the specific latent heat of fusion of ice. Given specific heat capacity of water is 4200

{k g}^{- 1} K^{- 1}

80 g

of water at

30^{o} C

is poured on large block of ice at

0^{\circ}

C. The mass of ice that melts is

Given, Latent heat =

334 J / g

Specific heat of water

= 4.2 J g^{- 1} C^{o - 1}

Join BYJU'S Learning Program

The enthalpy of fusion for ice is 334 J/g. How much is heat is absorbed if 10.0 grams of ice melts at 0∘C?

The correct option is A 3340 J3340J heat is absorbed if 10.0 grams of ice melts at 0 deg C.The enthalpy of fusion is 334 J/g.When 10.0 g of ice melts at 0 deg C, the heat absorbed is 10.0×334=3340 J

The enthalpy of fusion for ice is 334 J/g. How much is heat is absorbed if 10.0 grams of ice melts at $0^{\circ} C$ ?

The correct option is A 3340 J
3340J heat is absorbed if 10.0 grams of ice melts at 0 deg C.
The enthalpy of fusion is 334 J/g.
When 10.0 g of ice melts at 0 deg C, the heat absorbed is $10.0 \times 334 = 3340$ J