Question

The enthalpy of fusion of water is $1.435kcal.mol$. The molar entropy change for the melting of ice at $0^{o}C$ is:

• A. $5.260cal/\left(molK\right)$
• B. $0.526cal/\left(molK\right)$
• C. $10.52cal/\left(molK\right)$
• D. $21.04cal/\left(molK\right)$

Answer 1

Answer: (A)

$5.260cal/\left(molK\right)$

$\Delta S=\frac{\Delta H}{T}$
$\therefore$ The molar entropy change for the melting of ice = $\frac{1.435}{0+273}=5.26\ast {10}^{-3}Kcal/mol=5.26cal/mol$