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Byju's Answer
Standard XII
Chemistry
Enthalpy of Solution
The enthalpy ...
Question
The enthalpy of solution of anhydrous
C
u
S
O
4
is
−
16
kcal and that of
C
u
S
O
4
.5
H
2
O
is 3 kcal.. Calculate the enthalpy of hydration of
C
u
S
O
4
.
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Solution
C
u
S
O
4
(
s
)
+
a
q
⟶
C
u
S
O
4
(
a
q
)
△
H
=
−
16
K
C
a
l
(
C
u
S
O
4
.5
H
2
O
+
a
q
⟶
C
u
S
O
4
(
a
q
)
+
5
H
2
O
)
(
−
1
)
△
H
=
3
K
C
a
l
{reverse the reaction}
↓
△
H
=
−
3
K
C
a
l
C
u
S
O
4
+
5
H
2
O
⟶
C
u
S
O
4
.5
H
2
O
△
H
=
−
16
−
3
=
−
19
K
C
a
l
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0
Similar questions
Q.
The enthalpy of solution of anhydrous
C
u
S
O
4
is
−
15.9 kCal and that of
C
u
S
O
4
.5
H
2
O
is 2.8 kCal.
Calculate the enthalpy of hydration of
C
u
S
O
4
Q.
The enthalpies of solution of anhydrous
C
u
S
O
4
and
C
u
S
O
4
.5
H
2
O
are
−
15.89
and
2.80
k
c
a
l
/
m
o
l
respectively. The enthalpy of hydration of
C
u
S
O
4
to
C
u
S
O
4
.5
H
2
O
is:
Q.
Heat of solution of anhydrous
C
u
S
O
4
is -15.9 kcal and heat of hydration of anhydrous
C
u
S
O
4
is -18.9 kcal. The heat of solution of
C
u
S
O
4
.5
H
2
O
is ..........
Q.
The integral enthalpies of solution of anhydrous
C
u
S
O
4
(
s
)
and hydrated
C
u
S
O
4
.5
H
2
O
(
s
)
are
−
70
k
J
and
10
k
J
per mol respectively. Determine the magnitude of enthalpy of hydration of
0.1
mole anhydrous
C
u
S
O
4
(
s
)
as :
C
u
S
O
4
(
s
)
+
5
H
2
O
⟶
C
u
S
O
4
.5
H
2
O
.
Q.
The heat solution of anhydrous
C
u
S
O
4
is
−
15.9
k
c
a
l
and that of
C
u
S
O
4
.5
H
2
O
is
2.8
k
c
a
l
. Calculate the heat of hydration of
C
u
S
O
4
.
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