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Enthalpy of Solution

The enthalpy ...

Question

The enthalpy of solution of anhydrous $C u S O_{4}$ is $- 16$ kcal and that of $C u S O_{4} .5 H_{2} O$ is 3 kcal.. Calculate the enthalpy of hydration of $C u S O_{4}$ .

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Solution

$C u S O_{4} (s) + a q ⟶ C u S O_{4} (a q)$ $△ H = - 16 K C a l$
$(C u S O_{4} .5 H_{2} O + a q ⟶ C u S O_{4} (a q) + 5 H_{2} O) (- 1)$
$△ H = 3 K C a l$ {reverse the reaction}
$↓$
$△ H = - 3 K C a l$
$C u S O_{4} + 5 H_{2} O ⟶ C u S O_{4} .5 H_{2} O$ $△ H = - 16 - 3 = - 19 K C a l$

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