The enthalpy of the reaction forming PbO according to the following equation is 438kJ. What heat energy (kJ) is released in formation of 22.3gPbO(s)? (At. wt. Pb=207,O=16.0) 2Pb(s)+O2(g)→2PbO(s).
A
21.9
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B
28.7
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C
46.14
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D
34.2
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Solution
The correct option is B21.9 The given reaction is forming the 2 mole of PbO, it means
Wt Of PbO=2×223=446gm
∵ formation of 2 mol of PbO relaesed energy =438KJ
∴ formation of 1 mol of PbO will release energy =4382
∴ formation of .1 mol of PbO will release energy=438×.12=21.9KJ