Question

The equation $4_1^{1}H{\to }_2^{4}H{e}^{2+}+2e^{+}+26MeV$ represents.

• A. $\beta -decay$
• B. $\gamma -decay$
• C. Fusion
• D. Fission

Answer 1

The correct option is D Fission

$\begin{array}{c}4{}_1^{1}H⟶H{e}_2^4+2e_{+1}^0+26MeV\\ \text{This is an example of nucleur fission}\\ \text{Nucleur fission is the process in which nucleus}\\ \text{of an atom splits into two or more smaller}\\ \text{nuclei.}\end{array}$