The equation- 41H1 - - 2He4-2- - 2e- - - 26 MeV represents -

The correct option is D FusionAccording to the question, hydrogen is converted into helium and two #160;position #160;and energy. Here, this reaction corre ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Nuclear Fusion

The equation,...

Question

The equation, $4_{1} H^{1} \to [_{2} H e^{4}]^{2 +} + 2 e^{-}; + 26 M e V$ represents :

γ -

decay

No worries! We‘ve got your back. Try BYJU‘S free classes today!

β -

decay

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Fisslon

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Fusion

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D Fusion
According to the question, hydrogen is converted into helium and two position and energy. Here, this reaction corresponding fusion.

Suggest Corrections

Similar questions

4_{1} H^{1} \to_{2} H e^{4} + 2 e^{+} + 26 M e V

The above reaction represents

Q. The equation

4_{1}^{1} H \to_{2}^{4} H e^{2 +} + 2 e^{+} + 26 M e V

represents.

Q. The equation

4_{1}^{1} H^{2} \to_{2}^{4} H e^{2 +} + 2 e^{+ 1} + 26 M e V

represents

Q. A nucleus

_{11}^{24} N a

is β-radioactive. Write the equation representing β-decay.

Q. A nucleus

_{11}^{24} N a

β

-radioactive. Choose the equation representing

β

-decay.

Join BYJU'S Learning Program

The equation, 41H1→[2He4]2++2e−;+26MeV represents :

The correct option is D FusionAccording to the question, hydrogen is converted into helium and two position and energy. Here, this reaction corresponding fusion.

The equation, $4_{1} H^{1} \to [_{2} H e^{4}]^{2 +} + 2 e^{-}; + 26 M e V$ represents :

The correct option is D Fusion
According to the question, hydrogen is converted into helium and two position and energy. Here, this reaction corresponding fusion.