The equation x28−t+y2t−4=1 will represent an ellipse if
A
t∈(1,5)
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B
t∈(2,8)
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C
t∈(4,8)−{6}
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D
t∈(4,10)−{6}
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Solution
The correct option is Ct∈(4,8)−{6} Consider Equation, x2a2+y2b2=1 to represent an ellipse equation. a>0,b>0,a≠b Given,equation x2(8−t)+y2(t−4)=1 ⇒(8−t)>0 and (t−4)>0,(8−t)≠(t−4) ⇒t∈(−∞,8)∩(4,∞)∩ {t≠6} ⇒t∈(4,8)−{6}