The equation of a sphere with centre (−1,2,−3) and of radius 3 is
A
x2+y2+z2−2x+4y−6z+5=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x2+y2+z2+2x−4y+6z+5=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
x2+y2+z2−2x−4y+6z−5=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x2+y2+z2+2x+4y+6z+5=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Bx2+y2+z2+2x−4y+6z+5=0 Equation of sphere with centre (−1,2,−3) and radius 3 is given by (x+1)2+(y−2)2+(z+3)2=32 ⇒x2+y2+z2+2x−4y+6z+5=0