The equation of a straight line(s) passing through (1,2) and having intercept of length 3 units between the straight lines 3x+4y=24 and 3x+4y=12, is
A
y=2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x=1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
7x+24y+41=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
7x−24y+41=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct options are Bx=1 D7x−24y+41=0 Let the line passing through (1,2) makes an angle of α with the given parallel lines
Now the distance between the parallel lines is 125 units So, from diagram tanα=43 If the slope of the required line is m, then m= tan(θ±α) , where tanθ is slope of given line = −34 m=−3/4±4/31∓1=∞,724 So the equation of required lines are x=1,7x−24y+41=0