The equation of a tangent to the parabola y2=9x from the point (4,10) is
A
x−4y+36=0
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B
81x−8y−162=0
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C
9x−4y+4=0
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D
x−4y−36=0
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Solution
The correct options are Ax−4y+36=0 D9x−4y+4=0 Equation of tangent is y=mx+am Here a=9/4 Hence the equation is y=mx+94m Now the line passes through (4,10) 10=4m+94m 16m2−40m+9=0 m=14,94 Option A and C