Question

The equation of a transverse wave travelling along positive X axis with amplitude $0.2m$, velocity $360m/s$ and wavelength $60m$ can be written as:

• A. $y=0.2\sin \pi [6t+\frac{x}{60}]$
• B. $y=0.2\sin \pi [6t-\frac{x}{60}]$
• C. $y=0.2\sin 2\pi [6t-\frac{x}{60}]$
• D. $y=0.2\sin 2\pi [6t+\frac{x}{60}]$

Answer 1

The correct option is C $y=0.2\sin 2\pi [6t-\frac{x}{60}]$

Transverse wave travelling in positive x axis can be written as $y=Asin2\pi [\nu t-\frac{x}{\lambda }]$ ......(1)

Given : Wavelength $\lambda =60m$

Velocity $v=360m/s$

Amplitude $A=0.2m$

Using $v=\nu \lambda$ $⟹\nu =\frac{v}{\lambda }$

$\therefore$ $\nu =\frac{360}{60}=6$ $s^{-1}$

Putting all the values in (1), we get $y=0.2sin2\pi [6t-\frac{x}{60}]$