Question

The equation of a travelling wave is y = 60 cos (1800t – 6x) where y is in microns, t in seconds and x in metres. The ratio of maximum particle velocity to velocity of wave propagation is

• A. $3.6$
• B. $3.6\times {10}^{-5}$
• C. $3.6\times {10}^{-11}$
• D. $3.6\times {10}^{-4}$

Answer 1

The correct option is D

$3.6\times {10}^{-4}$

Maximum particle velocity $=\omega A$

Wave velocity $=\frac{\omega }{K}$

Therefore, the required ratio

$=\frac{\omega A}{\frac{\omega }{K}}=AK=60\times {10}^{-6}\times 6=3.6\times {10}^{-4}$