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Standard XII

Physics

Differential Equation of Wave

The equation ...

Question

The equation of a wave is $10 sin (6.28 x - 314 t)$ where $x$ is in centimeters and $t$ is in seconds. The maximum velocity of the particle is

62.8 c m s^{- 1}

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3140 m s^{- 1}

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50 c m s^{- 1}

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31.4 m s^{- 1}

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Solution

The correct option is C $31.4 m s^{- 1}$
The equation of the wave is given by,

$y = 10 sin (6.28 x - 314 t)$

$d y / d t = 10 \times 314 cos (6.28 x - 314 t)$

Therefore, the maximum velocity of the wave is $3140 c m / s$ or $31.4 m / s$

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The equation of a wave is 10sin(6.28x−314t) where x is in centimeters and t is in seconds. The maximum velocity of the particle is

The correct option is C 31.4 ms−1The equation of the wave is given by,y=10sin(6.28x−314t)dy/dt=10×314cos(6.28x−314t)Therefore, the maximum velocity of the wave is 3140cm/s or 31.4m/s

The equation of a wave is $10 sin (6.28 x - 314 t)$ where $x$ is in centimeters and $t$ is in seconds. The maximum velocity of the particle is

The correct option is C $31.4 m s^{- 1}$
The equation of the wave is given by,

$y = 10 sin (6.28 x - 314 t)$

$d y / d t = 10 \times 314 cos (6.28 x - 314 t)$

Therefore, the maximum velocity of the wave is $3140 c m / s$ or $31.4 m / s$