The equation of a wave travelling along positive $x -$ axis, as shown in figure at $t = 0$ is given by

sin (k x - ω t + \frac{π}{6})

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sin (k x - ω t - \frac{π}{6})

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sin (ω t - k x + \frac{π}{6})

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sin (ω t - k x - \frac{π}{6})

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Solution

The correct option is D $sin (ω t - k x - \frac{π}{6})$
{The equation of a wave travelling along positive x-axis is given by
$y = A sin (ω t - k x)$ . Here $A = 1.$ At $t = 0, y = - 0.5.$ $sin (- \frac{π}{6}) = - 0.5$ ,
so the equation of a wave travelling along positive x-asis, as shown in figure at $t = 0$ is given by
$y = A sin (ω t - k x - \frac{π}{6})$ .

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The equation of a wave travelling along positive x−axis, as shown in figure at t=0 is given by

The correct option is D sin(ωt−kx−π6){The equation of a wave travelling along positive x-axis is given byy=Asin(ωt−kx). Here A=1. At t=0,y=−0.5. sin(−π6)=−0.5, so the equation of a wave travelling along positive x-asis, as shown in figure at t=0 is given by y=Asin(ωt−kx−π6).

The equation of a wave travelling along positive $x -$ axis, as shown in figure at $t = 0$ is given by