Question

The equation of angular bisector between the pair of lines $xy+3x-2y-6=0$ is

• A. $x+y+1=0$
• B. $x^2-y^2=-5$
• C. $x-y-5=0$
• D. $xy=0$

Answer 1

Answer: (A), (C)

$x-y-5=0$

$xy+3x-2y-6=0$ $\Rightarrow (x-2)(y+3)=0$
$\Rightarrow x=2,y=-3$ lines which are parallel to co-ordinate axes.
$\therefore$ Angular bisectors will be parallel to $x+y=0$ and $x-y=0$ that passes through $(2,-3)$
$\therefore x+y+1=0$ and $x-y-5=0$ are the required angular bisector equations.