The equation of directrix of the parabola $3 y^{2} = 16 x$ is

3 x + 4 = 0

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3 x - 4 = 0

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- 3 x + 4 = 0

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Solution

The correct option is A $3 x + 4 = 0$
$3 y^{2} = 16 x$
$\Rightarrow y^{2} = \frac{16}{3} x$ is of the form $y^{2} = 4 a x$ which is a parabola
$\Rightarrow 4 a = \frac{16}{3}$
$\Rightarrow a = \frac{4}{3}$
Equation of directrix is $x = \frac{- 4}{3}$
or $3 x + 4 = 0$

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