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Question

The equation of line passing through the point (1,2) and perpendicular to the line x+y+1=0

A
yx+1=0
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B
yx1=0
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C
yx+2=0
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D
yx2=0
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Solution

The correct option is B yx1=0
Equation of the line perpendicular to the line x+y+1=0 is xy+c=0 Since this line passes to (1,2)
So,
12+c=0
1+c=0
c=1
Hence required equation of the line is
xy+1=0
yx1=0



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