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Question

The equation of perpendicular bisector of the line segment joining the points (−1,−2) and (2,0) is

A
5x+2y=1
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B
4x+6y=1
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C
6x+4y=1
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D
none of these
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Solution

The correct option is C 6x+4y=1
Mid point of points (1,2) and (2,0) is
(1+22,2+02)=(12,1)
Slope of line joining points (1,2) and (2,0) is
0+22+1=23
Hence slope of perpendicular line is 32
Therefore equation of line passing through (12,1) and slope 32 is
6x+4y=1

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