The equation of plane passing through $(1, 2, - 3), (0, 0, 0)$ and perpendicular to the plane $3 x - 5 y + 2 z = 1$ is

3 x + y + (\frac{5}{3}) z = 0

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x + y + z = 0

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9 x - 3 y + z = 0

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4 x + y + 2 z = 0

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Solution

The correct option is D $4 x + y + 2 z = 0$
$⎡ ⎢ ⎣ \begin{matrix} x & y & z 1 & 2 & - 3 3 & - 5 & 2 \end{matrix} ⎤ ⎥ ⎦ = 0 \Rightarrow x + y + z = 0$

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Similar questions

(1, 2, - 3)

3 x + y - 2 z = 5

2 x - 5 y - z = 7

(1, - 1, 2)

x + 2 y + 2 z = 5

3 x + 3 y + 2 z = 8

(1, - 3, - 2)

x + 2 y + 2 z = 5

3 x + 3 y + 2 z = 8

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