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Question

The equation of progressive wave in a wire is given by y=0.15 sin[2π(15tx10)]
Where the distance is in meters and time in seconds.
Determine i) amplitude, ii) frequency, iii) wavelength and iv) velocity of the wave

A
A=0.15 m,f=150 Hz, v=150 m/s, λ=1 m
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B
A=0.1 m,f=15 Hz, v=15 m/s, λ=1 m
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C
A=0.15 m,f=15 Hz, v=150 m/s, λ=10 m
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D
A=0.15 m,f=30 Hz, v=15 m/s, λ=10 m
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Solution

The correct option is C A=0.15 m,f=15 Hz, v=150 m/s, λ=10 m
y=0.15 sin[2π(15tx10)]=0.15 sin[30π(tx150)]
Comparing with standard wave equation y=A sin [ω(txv)], we get
A=0.15 m,f=ω2π=30π2π=15 Hz, v=150 m/s, λ=vf=10 m

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