The equation of progressive wave in a wire is given by $y = 0.15 s i n [2 π (15 t - \frac{x}{10})]$
Where the distance is in meters and time in seconds.
Determine i) amplitude, ii) frequency, iii) wavelength and iv) velocity of the wave

A = 0.15 m, f = 150 H z, v = 150 m / s, λ = 1 m

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A = 0.1 m, f = 15 H z, v = 15 m / s, λ = 1 m

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A = 0.15 m, f = 15 H z, v = 150 m / s, λ = 10 m

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A = 0.15 m, f = 30 H z, v = 15 m / s, λ = 10 m

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Solution

The correct option is C $A = 0.15 m, f = 15 H z, v = 150 m / s, λ = 10 m$
$y = 0.15 s i n [2 π (15 t - \frac{x}{10})] = 0.15 s i n [30 π (t - \frac{x}{150})]$
Comparing with standard wave equation $y = A s i n [ω (t - \frac{x}{v})]$ , we get
$A = 0.15 m, f = \frac{ω}{2 π} = \frac{30 π}{2 π} = 15 H z, v = 150 m / s, λ = \frac{v}{f} = 10 m$

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