You visited us 1 times! Enjoying our articles? Unlock Full Access!

f(x) Transforms to |f(x)|

The equation ...

Question

The equation of straight line in normal form is

x sec θ + y sin θ = p²

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x cos θ + ysin θ = p

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

y = mx + c

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $x c o s θ + y s i n θ = p$
The equation of straight line in terms of the length of perpendicular p from the origin upon it and the angle q which this perpendicular makes with the x-axis is x cos q + y sin q = p.

Suggest Corrections

Similar questions

θ

p

x cos θ + y sin θ = p

\sqrt{3} x + y + 2 = 0

θ

p

x cos θ + y sin θ = p

\sqrt{3} x + y + 2 = 0

θ

(2 cos θ + 3 sin θ) x + (3 cos θ - 5 sin θ) y - (5 cos θ - 2 sin θ) = 0

(2 c o s θ + 3 s i n θ) x + (3 c o s θ - 5 s i n θ) y - (5 c o s θ - 2 s i n θ) = 0

θ

x = a (cos θ + θ sin θ)

y = a (sin θ - θ cos θ)

θ

Join BYJU'S Learning Program