Question

The equation of straight line passing through point $A(-1,3,-2)$ and equally inclined to positive co-ordinate axes is

• A. $x+1=y-3=z+2$
• B. $\sqrt{3}x+1=\sqrt{3}y-3=\sqrt{3}z+2$
• C. $x+\sqrt{3}=y-3\sqrt{3}=z+2\sqrt{3}$
• D. $\frac{x+1}{\sqrt{3}}=\frac{y-3}{-\sqrt{3}}=\frac{z+2}{-\sqrt{3}}$

Answer 1

The correct option is A $x+1=y-3=z+2$

Let the d.c's of line is $(l,l,l)$ as it is equally inclined to positive co-ordinate axes.
$\Rightarrow$ d.r's is $a:b:c=1:1:1$
So, equation of line is given by: $\frac{x+1}{1}=\frac{y-3}{1}=\frac{z+2}{1}$
$\Rightarrow x+1=y-3=z+2$