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Question

The equation of tangent to parabola y2=32x at ends of its latus rectum is

A
xy+8=0
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B
x+y+8=0
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C
x+y8=0
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D
both (1) and (2)
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Solution

The correct option is C both (1) and (2)
Given parabola is y2=32x
So the end points of latus rectum are (a,±2a)=(8,±16)
Thus equation of tangent at these points are given by,T=0
(±16)y=32(x+82)
±y=x+8
x+y+8=0 & xy+8=0

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