The equation of tangent to parabola y2=32x at ends of its latus rectum is
A
x−y+8=0
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B
x+y+8=0
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C
x+y−8=0
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D
both (1) and (2)
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Solution
The correct option is C both (1) and (2) Given parabola is y2=32x So the end points of latus rectum are (a,±2a)=(8,±16) Thus equation of tangent at these points are given by,T=0 ⇒(±16)y=32(x+82) ⇒±y=x+8 ⇒x+y+8=0 & x−y+8=0