The equation of the axis of the parabola $9 y^{2} - 16 x - 12 y - 57 = 0$ is

2 x = 3

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y = 3

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3 y = 2

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x + 3 y = 3

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Solution

The correct option is B $3 y = 2$
On applying perfect square method we reduce the equation as $(y - \frac{2}{3})^{2} = \frac{16 x}{9} + \frac{61}{9}$
Thus the equation of axis will be $y = \frac{2}{3}$
Option C

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Similar questions

The axis of the parabola $9 y^{2} - 16 x - 12 y - 57 - 0$ is

9 y^{2} - 16 x - 12 y - 57 = 0

9 y^{2} - 16 x - 12 y - 57 = 0

9 y^{2} - 16 x - 12 y - 57 = 0

9 y^{2} - 16 x - 12 y - 57 = 0

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