The equation of the bisector of the angle between two lines $3 x - 4 y + 12 = 0$ and $12 x - 5 y + 7 = 0$ which contains the point $(- 1, 4)$ is

21 x + 27 y - 121 = 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

21 x - 27 y + 121 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

21 x + 27 y + 191 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{- 3 x + 4 y - 12}{5} = \frac{12 x - 5 y + 7}{13}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $21 x + 27 y - 121 = 0$
Equation to the bisector containing $(0, 0)$
$\frac{3 x - 4 y + 12}{5} = \frac{12 x - 5 y + 7}{13}$
$(- 1, 4)$
Check
$3 x - 1 - 4 \times 4 + 12 < 0$
$12 \times x - 1 - 3 \times 4 + 7 < 0$
$(- 1, 4)$ Lies is the opposite region as shown
So, equation,
$\frac{3 x - 4 y + 12}{5} = \frac{12 x - 5 y + 7}{13}$
$39 x - 52 y + 156 = 60 x - 25 y + 35$
$21 x + 27 y - 121 = 0$ .

Suggest Corrections

Similar questions

3 x - 4 y + 7 = 0

12 x - 5 y - 8 = 0

3 x - 4 y + 12 = 0

12 x - 5 y + 7 = 0

(- 1, 4)

3 x + 4 y + 5 = 0

12 x - 5 y - 7 = 0

Join BYJU'S Learning Program