The equation of the chord of the circle x2+y2=r2 passing through (2,3) and farthest from the centre is
A
x−3y+7=0
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B
2x+y−7=0
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C
2x+3y−13=0
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D
x+y−5=0
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Solution
The correct option is C2x+3y−13=0 The chord which is farthest from the centre (0,0) and passing through (2,3) is the chord which has midpoint at (2,3), so T=S1⇒2x+3y−r2=22+32−r2⇒2x+3y−13=0