The equation of the circle of radius 5 and touching the coordinate axes in third quadrant is
A
(x−5)2+(y+5)2=25
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B
(x+4)2+(y+4)2=25
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C
(x−6)2+(y+6)2=25
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D
(x+5)2+(y+5)2=25
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Solution
The correct option is D(x+5)2+(y+5)2=25 Since circle touches the co-ordinate axes in III quadrant. ∴ Radius = -h = -k. Hence h = k = -5 ∴ Equation of circle is (x+5)2+(y+5)2=25.