The equation of the circle whose centre lies on $y = x$ and which touches the lines $x + y = 1$ and $x + y = 3$ is

x^{2} + y^{2} + 2 x + 2 y + 1 = 0

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2 (x^{2} + y^{2}) - 4 (x + y) + 3 = 0

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x^{2} + y^{2} - 2 x - 2 y - 3 = 0

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Solution

The correct option is B $2 (x^{2} + y^{2}) - 4 (x + y) + 3 = 0$

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The equation of the circle whose centre lies on y=x and which touches the lines x+y=1 and x+y=3 is

The correct option is B 2(x2+y2)−4(x+y)+3=0

The equation of the circle whose centre lies on $y = x$ and which touches the lines $x + y = 1$ and $x + y = 3$ is

The correct option is B $2 (x^{2} + y^{2}) - 4 (x + y) + 3 = 0$