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Complex Numbers

The equation ...

Question

The equation of the hyperbola whose transverse axis is 14 and whose vertex bisects the distance between centre and the focus is

A

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B

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C

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D

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Solution

The correct option is C

Transverse axis $2 a = 14 \Rightarrow a = 7$

Vertex A is the mid point of centre C and focus $S \Rightarrow C S = 2. C A \Rightarrow a e = 2 a \Rightarrow e = 2$

$b^{2} = a^{2} (e^{2} - 1) \Rightarrow b^{2} = 147$

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