The equation of the hyperbola with vertices (3, 0), (–3, 0) and semi-latus rectum 4, is given by

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None of these

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Solution

The correct option is C
We have, a = 3 and $\frac{b^{2}}{a} = 4$ $\Rightarrow$ $b^{2} = 12$
Hence, the equation of the hyperbola is $\frac{x^{2}}{9} - \frac{y^{2}}{12} = 1$ $\Rightarrow$ $4 x^{2} - 3 y^{2} = 36$

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