The equation of the line having slope $= 3$ and passing through the point $(3, 4)$ is

y + 3 x + 4 = 0

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x + y - 7 = 0

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y - 3 x + 5 = 0

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x - y + 7 = 0

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Solution

The correct option is D $y - 3 x + 5 = 0$
$y = m x + c => 4 = 3 m + c => 4 = 3 \times 3 + c => c = 4 - 9 = - 5 y = m x + c => y = 3 x - 5 => y - 3 x + 5 = 0$

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