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Question

The equation of the line passing through the point (c,d) and parallel to the line ax+by+c=0 is

A
a(x+c)+b(y+d)=0
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B
a(x+c)b(y+d)=0
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C
a(xc)+b(yd)=0
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D
none of these
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Solution

The correct option is A a(xc)+b(yd)=0
Equation of line parallel to ax+by+c=0 is ax+by+k=0 where k is constant.

As this line passes through (c,d) then
ac+bd+k=0k=acbd
Therefore equation of line is
a(xc)+b(yd)=0

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