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Question

The equation of the line passing through the points (3,−2) and (−3,2) is

A
3y+2x=0
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B
2y+3x=0
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C
3y+2x+12=0
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D
3y+2x12=0
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Solution

The correct option is A 3y+2x=0
Given, the line is passing through the points (3,2) and (3,2)
So, we have slope of the line as m=y2y1x2x1=2(2)33=23
Thus, the equation of the line is given as
yy1=m(xx1)
y(2)=23(x3)
3(y+2)=2(x3)
3y+2x=0

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