The correct option is A 3y+2x=0
Given, the line is passing through the points (3,−2) and (−3,2)
So, we have slope of the line as m=y2−y1x2−x1=2−(−2)−3−3=−23
Thus, the equation of the line is given as
y−y1=m(x−x1)
⇒ y−(−2)=−23(x−3)
⇒ 3(y+2)=−2(x−3)
⇒ 3y+2x=0