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Question

The equation of the line passing through the points (4,−2) and (−3,3) is

A
7y5x+34=0
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B
7y+5x34=0
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C
7y5x+6=0
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D
7y+5x6=0
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Solution

The correct option is D 7y+5x6=0
Given, the line is passing through the points (4,2) and (3,3)
So, we have slope of the line as m=y2y1x2x1=3(2)34=57
Thus, the equation of the line is given as
yy1=m(xx1)
y(2)=57(x4)
7(y+2)=5(x4)
7y+5x6=0

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