Question

The equation of the line perpendicular to the line $2x+3y+5=0$ and passing through $(1,1)$, is

• A. $3x-2y+1=0$
• B. $3x-2y=2$
• C. $3x-2y=1$
• D. $3x-2y+2=0$

Answer 1

The correct option is C $3x-2y=1$

Equation of line perpendicular to the given line is
$3x-2y+\lambda =0...\left(i\right)$
Since, it passes through point $(1,1)$.
$\therefore 3-2+\lambda =0\Rightarrow \lambda =-1$
On putting the value of $\lambda$ in Eq. $\left(i\right)$, we get
$3x-2y-1=0$