The equation of the line through $(1, 2)$ and parallel to the line $3 x - 2 y + 4 = 0$ is

3 x - 2 y + 1 = 0

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3 x - 2 y - 1 = 0

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3 x + 2 y + 1 = 0

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3 x + 2 y - 1 = 0

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none of these

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Solution

The correct option is D $3 x - 2 y + 1 = 0$
Slope of line $3 x - 2 y + 4 = 0$ is
Slope $= \frac{3}{2}$
Thus the slope of the required line is $\frac{3}{2}$
The equation of the line is
$y - 2 = \frac{3}{2} (x - 1)$
$=> 2 y - 4 = 3 x - 3$
$=> 3 x - 2 y + 1 = 0$

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