The equation of the normal to the curve $2 y = 3 - x^{2}$ at the point $(1, 1)$

x - y = 0

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2 x + y = 3

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x + 2 y = 3

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x - y = 1

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Solution

The correct option is A $x - y = 0$
$2 y = 3 - x^{2}$

$\frac{d y}{d x} = - x = m$

Thus slope of normal at $(1, 1)$ is $= - {(\frac{1}{m})}_{(1, 1)} = 1$

Hence required normal is, $(y - 1) = 1 (x - 1) \Rightarrow x - y = 0$

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Similar questions

The normal at the point (1, 1) on the curve 2y + x² = 3 is

(A) x + y = 0 (B) x − y = 0

Q. The normal at the point (1, 1) on the curve 2 y + x 2 = 3 is (A) x + y = 0 (B) x − y = 0 (C) x + y + 1 = 0 (D) x − y = 1

Q. The equation of the normal to the curve y = x(2 − x) at the point (2, 0) is

(a) x − 2y = 2
(b) x − 2y + 2 = 0
(c) 2x + y = 4
(d) 2x + y − 4 = 0

Choose the correct answer in the following question:

The normal at the point (1, 1) on the curve $2 y + x^{2} = 3$ is

(a) x + y = 0 (b) x - y = 0 (c) x + y + 1 = 0 (d) x - y + 1 = 0

Q. The equation of normal to the curve

2 y = 3 - x^{2}

at the point

(1, 1)

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The equation of the normal to the curve 2y=3−x2 at the point (1,1)

The correct option is A x−y=02y=3−x2dydx=−x=mThus slope of normal at (1,1) is =−(1m)(1,1)=1Hence required normal is, (y−1)=1(x−1)⇒x−y=0

The equation of the normal to the curve $2 y = 3 - x^{2}$ at the point $(1, 1)$

The correct option is A $x - y = 0$
$2 y = 3 - x^{2}$

$\frac{d y}{d x} = - x = m$

Thus slope of normal at $(1, 1)$ is $= - {(\frac{1}{m})}_{(1, 1)} = 1$

Hence required normal is, $(y - 1) = 1 (x - 1) \Rightarrow x - y = 0$