The correct options are
C x−y−6=0
D x+y−6=0
The coordinates of the end points of latus rectum for parabola y2=8x are (2,4) and (2,−4).
The equation of the normal at point (x1,y1) on y2=4ax is
y−y1=−y12a(x−x1)
For the given parbola y2=8x⇒a=2
Putting (x1,y1)=(2,4) in above equation we get normal equation as
x+y−6=0
Similarly, the other equation of the normal at (2,−4) is
x−y−6=0