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Question

The equation of the perpendicular bisector of the line segment joining (2,1) and (3,4) is

A
x+3y10=0
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B
x+3y+10=0
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C
x3y10=0
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D
xy+10=0
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Solution

The correct option is A x+3y10=0
Mid point of line segment joining (2,1) and (3,4) (52,52)
Slope of the line joining (2,1) and (3,4)
m=4132=3
The required line is perpendicular to it, hence slope of the line =1m=13
Equation of perpendicular bisector : y52=13(x52)
2y5=13(2x5)x+3y10=0

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