The correct option is A 14x−5y−11z=19
Equation of plane passing through given line is given by,
a(x−1)+b(y+1)+cz=0
Also direction ratio of line are 2,−1,3
⇒2a−b+3c=0......(1)
and plane is parallel to direction with dr 3,4,2
⇒3a+4b+2c=0.....(2)
Solving (1) and (2), we get a=−14c11,b=5c11
Hence, required plane is
14x−5y−11z=19