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Question

The equation of the plane passing through the line x−12=y+1−1=z3 and parallel to the direction whose direction numbers are 3,4,2 is

A
14x5y11z=19
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B
3x+4y+2z+1=0
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C
2xy+3z=3
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D
none of these
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Solution

The correct option is A 14x5y11z=19
Equation of plane passing through given line is given by,
a(x1)+b(y+1)+cz=0
Also direction ratio of line are 2,1,3
2ab+3c=0......(1)
and plane is parallel to direction with dr 3,4,2
3a+4b+2c=0.....(2)
Solving (1) and (2), we get a=14c11,b=5c11
Hence, required plane is
14x5y11z=19

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