wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The equation of the plane passing through the line x−12=y+1−1=z3 and parallel to the direction whose direction numbers are 3,4,2 is

A
14x5y11z=19
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
3x+4y+2z+1=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2xy+3z=3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
none of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 14x5y11z=19
Equation of plane passing through given line is given by,
a(x1)+b(y+1)+cz=0
Also direction ratio of line are 2,1,3
2ab+3c=0......(1)
and plane is parallel to direction with dr 3,4,2
3a+4b+2c=0.....(2)
Solving (1) and (2), we get a=14c11,b=5c11
Hence, required plane is
14x5y11z=19

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Foot of Perpendicular, Image and Angle Bisector
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon