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Question

# The equation of the plane passing through the point (-1, 3, 2) and perpendicular to each of the planes x + 2y + 3z = 5 and 3x + 3y + = 0, is

A

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B

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C

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D

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Solution

## The correct option is B Given, equation of plane is passing throug the point (-1, 3, 2) ∴ A(x+1) + B(y-3) + C(z-2) = 0 ......(i) Since plane (i) is perpendicular to each of the planes x + 2y + 3z = 5 and 3x + 3y + z = 0 So, A + 2B + 3C = 0 and 3A + 3B + C = 0 ∴A2−9=B9−1=C3−6=K⇒A=−7K, B=8K, C=−3K Put the values of A, B and C in (i) we get, 7x - 8y + 3z + 25 = 0, which is the required equation of the plane.

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