The equation of the straight line which bisects the intercepts made by the axes on the lines $x + y = 2$ and $2 x + 3 y = 6$ is :

2 x = 3

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y = 1

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2 y = 3

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x = 1

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Solution

The correct option is D $y = 1$
Given lines are lines $x + y = 2$ and $2 x + 3 y = 6$
$x + y = 2$ cuts the x and y axis at $(2, 0), (0, 2)$ and
$2 x + 3 y = 6$ cuts the x and y axis at $(3, 0), (0, 2) .$
Hence, the equation of a straight line which bisects the intercepts made by the axes on the lines $x + y = 2$ and $2 x + 3 y = 6$ is given by $y = 3 - 2$ which is $y = 1.$

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Similar questions

x + y = 2

2 x + 3 y = 6

The equation of the diameter of the circle $x^{2} + y^{2} + 2 x - 4 y - 11 = 0$ which bisects the chords intercepted on the line $2 x - y + 3 = 0$ is

2 x + 3 y = 2, 3 x - 2 y = 4, x + 2 y = 3

2 x - y = 3

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