Question

The equation $\sin x+\sin y+\sin z=-3$ for $0\le x\le 2\pi ,0\le y\le 2\pi ,0\le z\le 2\pi$, has

• A. One solution
• B. Two sets of solutions
• C. Four sets of solutions
• D. No solution

Answer 1

The correct option is A One solution

$sinx+siny+sinz=-3$

only possible then $x=y=z={sin}^{-1}(-1)$

So, $x=y=z=3\Pi /2$

for $0\le x,y,x\le 2\pi$

So, Only one solution is possible.